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Formulas to Find Area

Formulas to find Area of Rectangle, Square, Parallelogram, Triangle, Circle, etc. - Aptitude Questions and Answers.

TIPS FOR SOLVING QUESTIONS RELATED TO AREA:


1. Square: A square is a plane figure with four equal straight sides and four right angles.

Area of Square = (side)2 = (diagonal)2 divided by 2

Perimeter of Square = 4 x side

2. Rectangle: A rectangle is a four-sided shape that is made up of two pairs of parallel lines and that has four right angles.

Area of Rectangle = Length x Breadth

Perimeter of Rectangle = 2(Length + Breadth)

3. Area of 4 walls of a room = 2(Length + Breadth) x Height

4. Triangle: A triangle is a a plane figure with three straight sides and three angles.

(i) Right triangle with base and height given.

triangle1


\begin{aligned} \text{Area of a triangle =} \frac{1}{2}*Base*Height \\
\end{aligned}

(ii) Triangle with three different sides a, b and c.

triangle2

\begin{aligned} \text{Area of a triangle =}\sqrt{s(s-a)(s-b)(s-c)}, \\
\end{aligned}
\begin{aligned}
s= \frac{1}{2}(a+b+c) \\
\end{aligned}


(iii) Equilateral triangle - A triangle with all three sides of equal length.

equilateral triangle

\begin{aligned} \text{Area of a equilateral triangle =} \frac{\sqrt{3}}{4}*(side)^2
\end{aligned}


(iv). Radius of incircle of an equilateral triangle of side a = \begin{aligned}
\frac{a}{2\sqrt{3}}
\end{aligned}

(v). Radius of circumcircle of an equilateral triangle of side a = \begin{aligned}
\frac{a}{\sqrt{3}}
\end{aligned}

(vi). Radius of incircle of a triangle of area a and semi-perimeter s = \begin{aligned}
\frac{a}{s}
\end{aligned}

5. Parallelogram: A parallelogram is a 4-sided flat shape with straight sides where opposite sides are parallel.

(i) Area of Parallelogram = Base x Height

(ii) Area of Rhombus = $MF#% \dfrac{1}{2} \text{ * } \left( \text{Product of diagonals} \right) $MF#%

(iii) Area of Trapezium = $MF#% \dfrac{1}{2} \text{ * } \left( \text{sum of parallel sides}* \text{distance between them} \right) $MF#%

6. Circle: A circle is a round plane figure whose boundary (the circumference) consists of points equidistant from a fixed point (the centre).
(i) \begin{aligned} \text{Area of a circle} = \pi R^2 \end{aligned}, where R is radius of the circle
(ii) \begin{aligned} \text{Circumference of a circle} = 2 \pi R \end{aligned}
(iii) \begin{aligned} \text{Length of a arc} = \frac{2 \pi R \theta }{360} \\
\text{ where } \theta \text{ is the central angle } \end{aligned}
(iv)
\begin{aligned} \text{Area of sector = } \frac{1}{2}(arc* \theta) \\
= \frac{\pi R^2 \theta}{360}
\end{aligned}
(v)
\begin{aligned} \text{Area of a semi circle =} \frac{\pi R^2}{2} \end{aligned}
(vi)
\begin{aligned}\text{Circumference of a semi circle =} \pi R \end{aligned}